{"id":4987,"date":"2022-10-13T18:17:04","date_gmt":"2022-10-13T18:17:04","guid":{"rendered":"https:\/\/www.studyzonebd.com\/math\/?p=4987"},"modified":"2022-10-13T18:22:21","modified_gmt":"2022-10-13T18:22:21","slug":"class-8-chapter-4-lesson-4-3","status":"publish","type":"post","link":"https:\/\/www.studyzonebd.com\/math\/class-8-chapter-4-lesson-4-3\/","title":{"rendered":"\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9 | \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf"},"content":{"rendered":"\n

\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf \u0997\u09a3\u09bf\u09a4 \u09ac\u0987 \u09b8\u09ae\u09cd\u09aa\u09c2\u09b0\u09cd\u09a3 \u09b8\u09ae\u09be\u09a7\u09be\u09a8 | Class Eight (08) Math <\/a>Book Solution | Chapter <\/a>04 : Algebraic formulas and applications| Class 8 math book Online Solution in Bangla (BD)<\/p>\n\n\n\n

\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997| \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9: \u0989\u09ce\u09aa\u09be\u09a6\u0995\u09c7 \u09ac\u09bf\u09b6\u09cd\u09b2\u09c7\u09b7\u09a3 – PDF<\/a><\/h4>\n\n\n\n

\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9 \u098f\u09b0 \u09b8\u0995\u09b2 \u09aa\u09cd\u09b0\u09b6\u09cd\u09a8 \u0993 \u0989\u09a4\u09cd\u09a4\u09b0 \u098f\u0996\u09be\u09a8\u09c7 \u09b0\u09df\u09c7\u099b\u09c7\u0964 \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf \u09b8\u09ae\u09cd\u09aa\u09c2\u09b0\u09cd\u09a3 \u0997\u09a3\u09bf\u09a4 \u09ac\u0987 \u09b8\u09ae\u09be\u09a7\u09be\u09a8<\/p>\n\n\n\n

\u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf\u09b0 \u0997\u09a3\u09bf\u09a4 \u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9 \u09aa\u09cd\u09b0\u09b6\u09cd\u09a8 \u0993 \u09b8\u09ae\u09be\u09a7\u09be\u09a8<\/strong><\/span><\/h4>\n\n\n\n

\u25a0<\/strong> \u09a8\u09bf\u099a\u09c7\u09b0 \u09b8\u09ae\u09c0\u0995\u09b0\u09a3\u09b8\u09ae\u09c1\u09b9 \u0989\u09ce\u09aa\u09be\u09a6\u0995\u09c7 \u09ac\u09bf\u09b6\u09cd\u09b2\u09c7\u09b7\u09a3 \u0995\u09b0\u0983<\/strong><\/p>\n\n\n\n

\u09aa\u09cd\u09b0\u09b6\u09cd\u09a8<\/span><\/strong><\/p>\n\n\n\n

\u09e7\u0964<\/strong> 3x – 75x3<\/sup>        \u09e8\u0964<\/strong> 4x2<\/sup> – y2<\/sup>       \u09e9\u0964<\/strong> 3ay2<\/sup> – 48a<\/p>\n\n\n\n

\u09ea\u0964<\/strong> a2<\/sup> – 2ab + b2<\/sup> – p2 <\/sup>   \u09eb\u0964<\/strong> 16y2<\/sup> – a2<\/sup> – 6a – 9    \u09ec\u0964<\/strong> 8a + ap3<\/sup><\/p>\n\n\n\n

\u09ed\u0964<\/strong> 2a3<\/sup> +16b3<\/sup>      \u09ee\u0964<\/strong> x2<\/sup> + y2<\/sup> – 2xy -1    \u09ef\u0964<\/strong> a2<\/sup> – 2ab + 2b -1<\/p>\n\n\n\n

\u09e7\u09e6\u0964<\/strong> x4<\/sup> – 6x2<\/sup> +1      \u09e7\u09e7\u0964<\/strong> 36 -12x + x2<\/sup>    \u09e7\u09e8<\/strong>\u0964 x6<\/sup> – y6<\/sup><\/p>\n\n\n\n

\u09e7\u09e9\u0964<\/strong> (x – y)3<\/sup> + z3<\/sup>     \u09e7\u09ea\u0964<\/strong> 64x3<\/sup> -8y3<\/sup>     \u09e7\u09eb\u0964<\/strong> x2<\/sup> +14x + 40<\/p>\n\n\n\n

\u09e7\u09ec\u0964<\/strong> x2 <\/sup>+ 7x -120      \u09e7\u09ed\u0964<\/strong> x2<\/sup> – 51x + 650      \u09e7\u09ee\u0964<\/strong> a2<\/sup> + 7ab +12b2<\/sup><\/p>\n\n\n\n

\u09e7\u09ef\u0964<\/strong> p2<\/sup> + 2 pq -80b2<\/sup>      \u09e8\u09e6\u0964<\/strong> x2<\/sup> – 3xy – 40y2<\/sup>   \u09e8\u09e7\u0964<\/strong> (x2<\/sup> – x)2<\/sup> + 3(x2<\/sup> – x) – 40<\/p>\n\n\n\n

\u09e8\u09e8\u0964<\/strong> (a2 + b2<\/sup> )2<\/sup> -18(a2 <\/sup>+ b2<\/sup> ) -88        \u09e8\u09e9\u0964<\/strong> (a2<\/sup> + 7a)2 <\/sup>-8(a2 + 7a) -180<\/p>\n\n\n\n

\u09e8\u09ea\u0964<\/strong> x2<\/sup> + (3a + 4b)x + (2a2<\/sup> + 5ab + 3b2<\/sup> )      \u09e8\u09eb\u0964<\/strong> 6x2<\/sup> – x -15<\/p>\n\n\n\n

\u09e8\u09ec\u0964<\/strong> x2<\/sup> – x – (a +1)(a + 2)       \u09e8\u09ed\u0964<\/strong> 3x2<\/sup> +11x – 4<\/p>\n\n\n\n

\u09e8\u09ee\u0964<\/strong> 3x2<\/sup> -16x -12       \u09e8\u09ef\u0964<\/strong> 2x2<\/sup> – 9x – 35      \u09e9\u09e6\u0964<\/strong> 2x2<\/sup> – 5xy + 2y2<\/sup><\/p>\n\n\n\n

\u09e9\u09e7\u0964<\/strong> x3<\/sup> – 8(x – y)3<\/sup>       \u09e9\u09e8\u0964<\/strong> 10p2<\/sup> +11pq – 6q2<\/sup>     \u09e9\u09e9\u0964<\/strong> 2(x + y)2<\/sup> – 3(x + y) – 2<\/p>\n\n\n\n

\u09e9\u09ea\u0964<\/strong>\u00a0ax2<\/sup>\u00a0+ (a2<\/sup>\u00a0+1)x + a\u00a0\u00a0\u00a0\u00a0\u00a0\u09e9\u09eb\u0964<\/strong>\u00a015x2<\/sup>\u00a0-11xy -12y2<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u09e9\u09ec\u0964<\/strong>\u00a0a3<\/sup>\u00a0– 3a2<\/sup>b + 3ab2<\/sup>\u00a0– 2b3<\/sup><\/p>\n\n\n\n

\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8<\/span><\/strong><\/p>\n\n\n\n

\u09e7\u0964 3x – 75x3<\/sup><\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8 :<\/p>\n\n\n\n

3x – 75x3<\/sup><\/p>\n\n\n\n

= 3x(1- 25x2<\/sup> )<\/p>\n\n\n\n

= 3x{(1) – (5x)2<\/sup>}<\/p>\n\n\n\n

= 3x(1+ 5x)(1- 5x)<\/p>\n\n\n\n

\u09e8\u0964 4x2<\/sup> – y2<\/sup><\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

            4x2<\/sup> – y2<\/sup><\/p>\n\n\n\n

                <\/sup>=(2x)2<\/sup>-y2<\/sup><\/p>\n\n\n\n

            =(2x+y)(2x-y)<\/p>\n\n\n\n

\u09e9\u0964 3ay2<\/sup> – 48a<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

3ay2<\/sup> – 48a<\/p>\n\n\n\n

            =3a(y2<\/sup> \u2013 16)<\/p>\n\n\n\n

            =3a(y2<\/sup>-42<\/sup>)<\/p>\n\n\n\n

            =3a(y-4)(y+4)<\/p>\n\n\n\n

\u09ea\u0964 a2<\/sup> – 2ab + b2<\/sup> – p2 <\/sup><\/strong> <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

a2<\/sup> – 2ab + b2<\/sup> – p2<\/sup><\/p>\n\n\n\n

                <\/sup>= (a –  b)2<\/sup> – p2<\/sup><\/p>\n\n\n\n

            =(a-b+p)(a-b-p)<\/p>\n\n\n\n

\u09eb\u0964 16y2<\/sup> – a2<\/sup> – 6a – 9<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

16y2<\/sup> – a2<\/sup> – 6a \u2013 9<\/p>\n\n\n\n

            =(4y)2<\/sup> \u2013( a2<\/sup> + 2.a.3 \u2013 32<\/sup>)<\/p>\n\n\n\n

            =(4y)2<\/sup>-(a+3)2<\/sup><\/p>\n\n\n\n

            ={(4y+(a+3)}{(4y-(a+3)}<\/p>\n\n\n\n

            =(4y+a+3)(4y-a-3)<\/p>\n\n\n\n

\u09ec\u0964 8a + ap3<\/sup><\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

8a + ap3<\/sup><\/p>\n\n\n\n

            =a(8 + p3<\/sup>)<\/p>\n\n\n\n

            =a(23<\/sup>+pp3<\/sup>)<\/p>\n\n\n\n

            =a(2+p)(22<\/sup>+2.p+p2<\/sup>)<\/p>\n\n\n\n

            =a(2+pp)(4+2p+pp2<\/sup>)<\/p>\n\n\n\n

\u09ed\u0964 2a3<\/sup> +16b3<\/sup><\/strong> <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

2a3<\/sup> +16b3<\/sup>       <\/p>\n\n\n\n

            =2(a3<\/sup> +8b3<\/sup>)<\/p>\n\n\n\n

            =2{a3<\/sup>+(2b)3<\/sup>}<\/p>\n\n\n\n

            =2(a+2b){(a)2<\/sup>+a.2b+(2b)2<\/sup>}<\/p>\n\n\n\n

            =2(a+2b)(a2<\/sup>+2ab+4b2<\/sup>)<\/p>\n\n\n\n

 \u09ee\u0964 x2<\/sup> + y2<\/sup> – 2xy -1 <\/strong>  <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> + y2<\/sup> – 2xy -1<\/p>\n\n\n\n

            = x2<\/sup> – 2xy+ y2<\/sup> -1<\/p>\n\n\n\n

            =(x-y)2<\/sup>-12<\/sup><\/p>\n\n\n\n

            =(x-y+1)(x-y-1)<\/p>\n\n\n\n

\u09ef\u0964 a2<\/sup> – 2ab + 2b -1<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

a2<\/sup> – 2ab + 2b -1<\/p>\n\n\n\n

            = (a2<\/sup> -1)- 2b(a -1)<\/p>\n\n\n\n

            =(a-1)(a+1)-2b(a-1)<\/p>\n\n\n\n

            =(a-1)(a+1-2b)<\/p>\n\n\n\n

\u09e7\u09e6\u0964 x4<\/sup> – 6x2<\/sup> +1<\/strong>          <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x4<\/sup> – 6x2<\/sup> +1      <\/p>\n\n\n\n

            =(x2 <\/sup>)2<\/sup> \u2013 2.x2<\/sup> .1+12<\/sup>-4x2<\/sup><\/p>\n\n\n\n

            =(x2<\/sup>-1)2<\/sup>-(2x)2<\/sup><\/p>\n\n\n\n

                <\/sup>=(x2<\/sup>-1+2x)(x2<\/sup>-1-2x)<\/p>\n\n\n\n

\u09e7\u09e7\u0964 36 -12x + x2<\/sup> <\/strong>       <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

36 -12x + x2<\/sup><\/p>\n\n\n\n

                <\/sup>=x2<\/sup>-2.x.6+62<\/sup><\/p>\n\n\n\n

            =(x-6)2<\/sup><\/p>\n\n\n\n

                <\/sup>=(x-6)(x+6)<\/p>\n\n\n\n

\u09e7\u09e8\u0964 x6<\/sup> – y<\/strong>6<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x6<\/sup> – y6<\/sup><\/p>\n\n\n\n

=(x3<\/sup>)2<\/sup>-(y3<\/sup>)2<\/sup><\/p>\n\n\n\n

=(x3<\/sup>+Y3<\/sup>)( x3<\/sup>-Y3<\/sup>)<\/p>\n\n\n\n

=(X+Y)(X2<\/sup>-XY+Y2<\/sup>)(X-Y)(X2<\/sup>+XY-Y2<\/sup>)<\/p>\n\n\n\n

=(X+Y) (X-Y)(X2<\/sup>-XY+Y2<\/sup>) (X2<\/sup>+XY-Y2<\/sup>)<\/p>\n\n\n\n

\u09e7\u09e9\u0964 (x – y)3<\/sup> + z<\/strong>3<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

(x – y)3<\/sup> + z3<\/sup><\/p>\n\n\n\n

            ={(x – y) + z}{(x-y)2<\/sup>-(x-y)z+z2<\/sup>}<\/p>\n\n\n\n

            =(x-y+z)(x2<\/sup>-2xy+y2<\/sup>-xz+yz+z2<\/sup>)<\/p>\n\n\n\n

\u09e7\u09ea\u0964 64x3<\/sup> -8y3<\/sup><\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

64x3<\/sup> -8y3<\/sup><\/p>\n\n\n\n

=8(8x3<\/sup> -y3<\/sup>)<\/p>\n\n\n\n

=8{(2x)3<\/sup>-y3<\/sup>)}<\/p>\n\n\n\n

=8(2x-y){(2x)2<\/sup>+2.x.y+(y)2<\/sup>}<\/p>\n\n\n\n

=8(2x-y)(4x2<\/sup>+2xy+y2<\/sup>)<\/p>\n\n\n\n

\u09e7\u09eb\u0964 x2<\/sup> +14x + 40<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> +14x + 40<\/p>\n\n\n\n

            = x2<\/sup> +4x+10x + 40<\/p>\n\n\n\n

            =x(x+4)+10(x+4)<\/p>\n\n\n\n

            =(x+4)(x+10)<\/p>\n\n\n\n

\u09e7\u09ec\u0964 x2 <\/sup>+ 7x -120 <\/strong>      <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2 <\/sup>+ 7x -120<\/p>\n\n\n\n

            = x2 <\/sup>+ 15x-8x -120<\/p>\n\n\n\n

            =x(x+15)-8(x+15)<\/p>\n\n\n\n

            =(x-8)(x+15)<\/p>\n\n\n\n

\u09e7\u09ed\u0964 x2<\/sup> – 51x + 650<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> – 51x + 650<\/p>\n\n\n\n

            = x2<\/sup> – 26x-25x + 650<\/p>\n\n\n\n

            =x(x-26)-25(x-26)<\/p>\n\n\n\n

            =(x-25)(x-26)<\/p>\n\n\n\n

\u09e7\u09ee\u0964 a2<\/sup> + 7ab +12b<\/strong>2<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

a2<\/sup> + 7ab +12b2<\/sup><\/p>\n\n\n\n

            = a2<\/sup> + 3ab+4ab +12b2<\/sup><\/p>\n\n\n\n

            =a(a+3b)+4b(a+3b)<\/p>\n\n\n\n

            =(a+4b)(a+3b)<\/p>\n\n\n\n

\u09e7\u09ef\u0964 p2<\/sup> + 2 pq -80b2<\/sup>  <\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

p2<\/sup> + 2 pq -80b2<\/sup>          <\/p>\n\n\n\n

            = p2<\/sup> + 10pq-8pq -80b2<\/sup>         <\/p>\n\n\n\n

            =p(p+10q)-8q(p+10q)<\/p>\n\n\n\n

            =(p-8q)(p+10q)<\/p>\n\n\n\n

\u09e8\u09e6\u0964 x2<\/sup> – 3xy – 40y2<\/sup> <\/strong>   <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> – 3xy – 40y2<\/sup><\/p>\n\n\n\n

            = x2<\/sup> – 8xy+5xy – 40y2<\/sup><\/p>\n\n\n\n

            =x(x-8y)+5y(x-8y)<\/p>\n\n\n\n

            =(x+5y)(x-8y)<\/p>\n\n\n\n

\u09e8\u09e7\u0964 (x2<\/sup> – x)2<\/sup> + 3(x2<\/sup> – x) \u2013 40<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

\u09ae\u09a8\u09c7 \u0995\u09b0\u09bf, x2<\/sup> \u2013 x=a<\/p>\n\n\n\n

\u09aa\u09cd\u09b0\u09be\u09aa\u09cd\u09a4 \u09b0\u09be\u09b6\u09bf=a2<\/sup>+3a-40<\/p>\n\n\n\n

            = a2<\/sup>+8a-5a-40<\/p>\n\n\n\n

            =a(a+8)-5(a+8)<\/p>\n\n\n\n

            =(a-5)(a+8)<\/p>\n\n\n\n

            =(x2<\/sup>-x-5)(x2<\/sup>-x+8) [\u09ae\u09be\u09a8 \u09ac\u09b8\u09bf\u09af\u09bc\u09c7]<\/p>\n\n\n\n

\u09e8\u09e8\u0964 (a2<\/sup> + b2<\/sup> )2<\/sup> -18(a2 <\/sup>+ b2<\/sup> ) -88<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

\u09a7\u09b0\u09bf,  a2<\/sup> + b2<\/sup>=x<\/p>\n\n\n\n

\u09aa\u09cd\u09b0\u09a6\u09a4\u09cd\u09a4 \u09b0\u09be\u09b6\u09bf=x2<\/sup>-18x-88<\/p>\n\n\n\n

            = x2<\/sup>-22x+4x-88<\/p>\n\n\n\n

            =x(x-22)+4(x-22)<\/p>\n\n\n\n

            =(x+4)(x-22)<\/p>\n\n\n\n

            =( a2<\/sup> + b2<\/sup>+4)( a2<\/sup> + b2<\/sup>-22)<\/p>\n\n\n\n

\u09e8\u09e9\u0964 (a2<\/sup> + 7a)2 <\/sup>-8(a2 + 7a) -180<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

\u09ae\u09a8\u09c7 \u0995\u09b0\u09bf, a2<\/sup> + 7a=x<\/p>\n\n\n\n

\u09aa\u09cd\u09b0\u09a6\u09a4\u09cd\u09a4 \u09b0\u09be\u09b6\u09bf=x2<\/sup>-8x-180<\/p>\n\n\n\n

            = x2<\/sup>-18x+10x-180<\/p>\n\n\n\n

            =x(x-18)+10(x-18)<\/p>\n\n\n\n

            =(x+10)(x-18)<\/p>\n\n\n\n

            =( a2<\/sup> + 7a+10)( a2<\/sup> + 7a-18)<\/p>\n\n\n\n

\u09e8\u09ea\u0964 x2<\/sup> + (3a + 4b)x + (2a2<\/sup> + 5ab + 3b2<\/sup> )<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> + (3a + 4b)x + (2a2<\/sup> + 5ab + 3b2<\/sup> )<\/p>\n\n\n\n

            = x2<\/sup> + (3a + 4b)x + (2a2<\/sup> + 3ab+2ab + 3b2<\/sup> )<\/p>\n\n\n\n

            = x2<\/sup> + (3a + 4b)x +{a(2a+3b)+b(2a+3b)<\/p>\n\n\n\n

            = x2<\/sup> + (3a + 4b)x +(a+b)(2a+3b)<\/p>\n\n\n\n

            = x2<\/sup> + (2a + 3b)x+(a+b)x +(a+b)(2a+3b)<\/p>\n\n\n\n

            =x(x+2a+3b)+(a+b)(x+2a+3b)<\/p>\n\n\n\n

            =(x+a+b)(x+2a+3b)<\/p>\n\n\n\n

\u09e8\u09eb\u0964 6x2<\/sup> – x -15<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

6x2<\/sup> – x -15<\/p>\n\n\n\n

            =6x2<\/sup> – 10x+9x -15<\/p>\n\n\n\n

            =2x(3x-5)+3(3x-5)<\/p>\n\n\n\n

            =(2x+3)(3x-5)<\/p>\n\n\n\n

\u09e8\u09ec\u0964 x2<\/sup> – x – (a +1)(a + 2)<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x2<\/sup> – x – (a +1)(a + 2)<\/p>\n\n\n\n

            = x2<\/sup> – x – (a +1)(a + 1+1)<\/p>\n\n\n\n

            = x2<\/sup> – x – m(m+1)  [a+1=m \u09a7\u09b0\u09c7]<\/p>\n\n\n\n

            =x2<\/sup>-x-m2<\/sup>-m<\/p>\n\n\n\n

            = x2<\/sup>-m2<\/sup>-x-m<\/p>\n\n\n\n

            =(x-m)(x+m)-1(x+m)<\/p>\n\n\n\n

            =(x+m)(x-m-1)<\/p>\n\n\n\n

            =(x+a+1)(x-a-1-1) [\u09ae\u09be\u09a8 \u09ac\u09b8\u09bf\u09af\u09bc\u09c7]<\/p>\n\n\n\n

            =(x+a+1)(x-a-2)<\/p>\n\n\n\n

\u09e8\u09ed\u0964 3x2<\/sup> +11x \u2013 4<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

3x2<\/sup> +11x \u2013 4<\/p>\n\n\n\n

            =3x2<\/sup> +12x-x \u2013 4<\/p>\n\n\n\n

            =3x(x+4)-1(x+4)<\/p>\n\n\n\n

            =(3x-1)(x+4)<\/p>\n\n\n\n

\u09e8\u09ee\u0964 3x2<\/sup> -16x -12<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

3x2<\/sup> -16x -12<\/p>\n\n\n\n

            =3x2<\/sup> -18x-2x -12<\/p>\n\n\n\n

            =3x(x-6)-2(x-6)<\/p>\n\n\n\n

            =(3x-2)(x-6)<\/p>\n\n\n\n

\u09e8\u09ef\u0964 2x2<\/sup> – 9x – 35<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

2x2<\/sup> – 9x \u2013 35<\/p>\n\n\n\n

            =2x2<\/sup> – 14x-5x \u2013 35<\/p>\n\n\n\n

            =2x(x-7)-5(x-7)<\/p>\n\n\n\n

            =(2x-5)(x-7)<\/p>\n\n\n\n

\u09e9\u09e6\u0964 2x2<\/sup> – 5xy + 2y<\/strong>2<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

2x2<\/sup> – 5xy + 2y2<\/sup><\/p>\n\n\n\n

                <\/sup>=2x2<\/sup> – 4xy-xy + 2y2<\/sup><\/p>\n\n\n\n

            =2x(x-2y)-y(x-2y)<\/p>\n\n\n\n

            =(2x-y)(2x-y)<\/p>\n\n\n\n

\u09e9\u09e7\u0964 x3<\/sup> – 8(x – y)3<\/sup> <\/strong>       <\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

x3<\/sup> – 8(x – y)3<\/sup><\/p>\n\n\n\n

            = (x)3<\/sup> \u2013 {2(x – y)}3<\/sup><\/p>\n\n\n\n

            =(x)3<\/sup> \u2013 {2x -2 y}3<\/sup><\/p>\n\n\n\n

            ={x-(2x-2y){(x)2<\/sup>+x(2x-2y)+(2x-2y)2<\/sup>}<\/p>\n\n\n\n

            =(x-2x+2y){x2<\/sup>+2x2<\/sup>-2xy+(2x)2<\/sup>-2.2x.2y+(2y)2<\/sup>}<\/p>\n\n\n\n

            =(x-2x+2y)( 3x2<\/sup>-2xy+4x2<\/sup>-8x.y+4y2<\/sup>)<\/p>\n\n\n\n

            =(2y-x)(7x2<\/sup>-10xy+4y2<\/sup>)<\/p>\n\n\n\n

\u09e9\u09e8\u0964 10p2<\/sup> +11pq – 6q<\/strong>2<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

10p2<\/sup> +11pq – 6q2<\/sup><\/p>\n\n\n\n

                <\/sup>=10p2<\/sup> +15pq-4pq – 6q2<\/sup><\/p>\n\n\n\n

            =5p(2p+3q)-2q(2p+3q)<\/p>\n\n\n\n

            =(5p-2q)(2p+3q)<\/p>\n\n\n\n

\u09e9\u09e9\u0964 2(x + y)2<\/sup> – 3(x + y) \u2013 2<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

\u09a7\u09b0\u09bf, x+y=a<\/p>\n\n\n\n

\u09aa\u09cd\u09b0\u09a6\u09a4\u09cd\u09a4 \u09b0\u09be\u09b6\u09bf=2(a)2<\/sup> – 3(a) \u2013 2<\/p>\n\n\n\n

            =2a2<\/sup> – 4a+a \u2013 2<\/p>\n\n\n\n

            =2a(a-2)+1(a-2)<\/p>\n\n\n\n

            =(2a+1)(a-2)<\/p>\n\n\n\n

            =(2x+2y+1)(x+y-2)<\/p>\n\n\n\n

\u09e9\u09ea\u0964 ax2<\/sup> + (a2<\/sup> +1)x + a<\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

ax2<\/sup> + (a2<\/sup> +1)x + a<\/p>\n\n\n\n

            = ax2<\/sup> + a2<\/sup> x+x + a<\/p>\n\n\n\n

            =ax(x+a)+1(x+a)<\/p>\n\n\n\n

            =(ax+1)(x+1)<\/p>\n\n\n\n

\u09e9\u09eb\u0964 15x2<\/sup> -11xy -12y2<\/sup><\/strong><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

15x2<\/sup> -11xy -12y2<\/sup><\/p>\n\n\n\n

            =15x2<\/sup> -20xy+9xy -12y2<\/sup><\/p>\n\n\n\n

            =5x(3x-4y)+3y(3x-4y)<\/p>\n\n\n\n

            =(3x-4y)(5x+3y)<\/p>\n\n\n\n

\u09e9\u09ec\u0964 a3<\/sup> – 3a2<\/sup>b + 3ab2<\/sup> – 2b<\/strong>3<\/strong><\/sup><\/p>\n\n\n\n

\u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983<\/p>\n\n\n\n

a3<\/sup> – 3a2<\/sup>b + 3ab2<\/sup> – 2b3<\/sup><\/p>\n\n\n\n

= a3<\/sup> – 3a2<\/sup>b + 3ab2<\/sup> – b3<\/sup>-b3<\/sup><\/p>\n\n\n\n

=(a-b)3<\/sup>-b3<\/sup><\/p>\n\n\n\n

=(a-b-b){(a-b)2<\/sup>+(a-b).b+b2<\/sup>}<\/p>\n\n\n\n

=(a-2b)(a2<\/sup>-2ab+b2<\/sup>+ab-b2<\/sup>+b2<\/sup>)<\/p>\n\n\n\n

=(a-2b)(a2<\/sup>-ab+b2<\/sup>)<\/p>\n\n\n\n

\n\n\n\n
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tags: <\/em>Bangladesh, Bangla, Bengali, Class 8\/JSC math BD, Class eight math solution bd, class 8 math pdf download, \u0985\u09b7\u09cd\u099f\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf\u09b0 \u0997\u09a3\u09bf\u09a4 \u09b8\u09ae\u09be\u09a7\u09be\u09a8\u0983 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ea.\u09e9 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09df \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09df\u09cb\u0997\u0964 \u0989\u09ce\u09aa\u09be\u09a6\u0995\u09c7 \u09ac\u09bf\u09b6\u09cd\u09b2\u09c7\u09b7\u09a3\n<\/pre>\n","protected":false},"excerpt":{"rendered":"
\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf \u0997\u09a3\u09bf\u09a4 \u09ac\u0987 \u09b8\u09ae\u09cd\u09aa\u09c2\u09b0\u09cd\u09a3 \u09b8\u09ae\u09be\u09a7\u09be\u09a8 | Class Eight (08) Math Book Solution | Chapter 04 : Algebraic formulas and applications| Class 8 math book Online Solution in Bangla (BD) \u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997| \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9: \u0989\u09ce\u09aa\u09be\u09a6\u0995\u09c7 \u09ac\u09bf\u09b6\u09cd\u09b2\u09c7\u09b7\u09a3 – PDF \u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 […]<\/p>\n","protected":false},"author":1,"featured_media":4919,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[36],"tags":[37,38],"class_list":["post-4987","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-eight-8","tag-class-8","tag-class-eight"],"yoast_head":"\n\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9 | \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf - Study Zone BD<\/title>\n<meta name=\"description\" content=\"\u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf \u0997\u09a3\u09bf\u09a4 \u09ac\u0987 \u09b8\u09ae\u09cd\u09aa\u09c2\u09b0\u09cd\u09a3 \u09b8\u09ae\u09be\u09a7\u09be\u09a8 | Class Eight (08) Math Book Solution. Chapter 04 : Algebraic formulas and applications \u0989\u09ce\u09aa\u09be\u09a6\u0995\u09c7 \u09ac\u09bf\u09b6\u09cd\u09b2\u09c7\u09b7\u09a3\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.studyzonebd.com\/math\/class-8-chapter-4-lesson-4-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u09ea\u09b0\u09cd\u09a5 \u0985\u09a7\u09cd\u09af\u09be\u09df\u0983 \u09ac\u09c0\u099c\u0997\u09a3\u09bf\u09a4\u09c0\u09af\u09bc \u09b8\u09c2\u09a4\u09cd\u09b0\u09be\u09ac\u09b2\u09bf \u0993 \u09aa\u09cd\u09b0\u09af\u09bc\u09cb\u0997 | \u0985\u09a8\u09c1\u09b6\u09c0\u09b2\u09a8\u09c0 \u09ea.\u09e9 | \u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf - Study Zone BD\" \/>\n<meta property=\"og:description\" content=\"\u09ee\u09ae \u09b6\u09cd\u09b0\u09c7\u09a3\u09bf \u0997\u09a3\u09bf\u09a4 \u09ac\u0987 \u09b8\u09ae\u09cd\u09aa\u09c2\u09b0\u09cd\u09a3 \u09b8\u09ae\u09be\u09a7\u09be\u09a8 | Class Eight (08) Math Book Solution. 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